Submited on : | Tue, 12th of Feb 2019 - 13:33:45 PM |

Subreddit : | heraldry |

Author : | HeraldicArtist |

Comments : | 9 |

Points : | 17 |

UPVOTED : | 81% |

Post ID : | aptddc |

Post Name : | t3_aptddc |

Post Type : | link |

Subreddit Type : | public |

Subreddit ID : | t5_2r04o |

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Can someone explain what is going on here for someone who is bad at math? Maybe with an example?

I am also bad at math, but okay at geometry. That said, I never really knew about classical geometry until a recent post by u/HeraldicArtist explained it a bit.

In this case, u/HeraldicArtist drew the rectangle and an "X" from corner to corner (the "X" simply gives him a centerpoint, which would be helpful for a fesswise division). Doesn’t matter what size the rectangle is—in classical geometry, things are measured by points where lines intersect, not by relying on units of measurement.

Using a compass, u/HeraldicArtist made a semicircle from one of the lower corners to the other. At the highest point of that semicircle he drew a line straight across. From that line, he did the same thing with the compass except he did it upside-down. He’d then erase the first semicircle and the line that guided the second, and he’d be left with a well-balanced shield shape.

One aspect of u/HeraldicArtist’s use of classical geometry is that he also uses it for shield divisions, and with a shield divided fesswise the lower half seems small to me. It took some getting used to, but I appreciate it now.

Thank your for the explanation better than mine!

Impecable manera de dibujar la boca del escudo. Estoy aprendiendo geometría contigo, Antonio.

Muchas gracias, como bien habías adivinado tocaba Castilla, aunque sólo sea un excusa para trazar un escudo con su arco de medio punto.

I draw with center Cp an arc of radius b / 2 that crosses the axis of vertical symmetry. This crossing point Ca will be the center of the semicircular arc. The horizontal tangent H1 to this arc marks the meeting points Pd (dexter) and Ps (sinister) of the 2 vertical sides of the CoA with its semicircular arc at base. This method belongs to the constructive geometry, and the expression 7h/12 is not needed, it is only a check using analytic geometry and valid only for the ratio 5:6 (b:h).

Thank you so much for this!

Thanks to you!